jsk_fellows (view)

2 rows where "created_at" is on date 2009-03-24

Search:

- remove filter - id name description location url twitter fellowship followers_count created_at verified screen_name

= != contains ends with starts with > ≥ < ≤ like not like glob in not in array contains date is null is not null is blank is not blank

- column - id name description location url twitter fellowship followers_count created_at verified screen_name

= != contains ends with starts with > ≥ < ≤ like not like glob in not in array contains date is null is not null is blank is not blank

Sort... Sort by id Sort by name Sort by description Sort by location Sort by url Sort by twitter Sort by fellowship Sort by followers_count Sort by created_at Sort by verified Sort by screen_name

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id	name	description	location	url	twitter	fellowship	followers_count	created_at	verified	screen_name
26334203	Andrew Maykuth	Philadelphia Inquirer business reporter. I cover energy and gambling. Go figure.	Philadelphia, Pa.	http://www.philly.com	https://twitter.com/Maykuth	jsk-fellows2003	2641	2009-03-24T21:52:53+00:00	1	Maykuth
26336913	Frances Robles	I cover Puerto Rico, Central America, and file investigative reports from Florida and beyond for the @nytimes. https://www.nytimes.com/by/frances-robles?8qa	Florida, USA	http://www.nytimes.com/by/frances-robles	https://twitter.com/FrancesRobles	jsk-fellows2005	23422	2009-03-24T22:05:08+00:00	1	FrancesRobles

CREATE VIEW jsk_fellows AS 
    select
        users.id,
        users.name,
        users.description,
        users.location,
        users.url,
        'https://twitter.com/' || users.screen_name as twitter,
        group_concat(lists.slug) as fellowship,
        users.followers_count,
        users.created_at,
        users.verified,
        users.screen_name
    from users
        join list_members
            on list_members.user = users.id
        join lists
            on list_members.list = lists.id
    where
        lists.slug like 'jsk-fellows%'
        and lists.slug not like '%projects'
    group by users.id;