jsk_fellows (view)

5 rows where location = "Boston, MA"

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Suggested facets: verified, created_at (date)

id name description location url fellowship followers_count created_at verified screen_name
48068105 Beth Daley Editor and General Manager @ConversationUS. Proud alum of @InsideClimate, @NECIRBU, @BostonGlobe, @JSKStanford. Boston, MA https://theconversation.com/us jsk-fellows2012 3327 2009-06-17T18:49:40+00:00 0 BethBDaley
63027773 Wilson Lievano Senior Digital Editor @GroundTruth. News animator. Knight Fellow. Explaining the world one keyframe at a time. Boston, MA http://www.animatedpress.com jsk-fellows2013 514 2009-08-05T04:08:38+00:00 1 wlievano
63125158 Alex Beam This is a Twitter bot. The real Alex Beam, distinguished Boston Globe writer and squash enthusiast, is found at @ImAlexBeamYrNot Boston, MA http://bostonglobe.com/staff/beam jsk-fellows1997 518 2009-08-05T13:02:51+00:00 0 GlobeAlexBeam
230879206 Sean P. Murphy Reporter @Boston Globe, Suffolk University journalism professor, regular on the Red Line Boston, MA http://bostonglobe.com jsk-fellows2000 1407 2010-12-27T00:02:17+00:00 0 spmurphyboston
1370570863 Sacha Pfeiffer @NPR reporter. Former reporter for @BostonGlobe & @GlobeSpotlight. Former @WBUR host & reporter. @JSKStanford fellow. @SpotlightMovie fan. spfeiffer@npr.org Boston, MA https://www.npr.org/people/676406186/sacha-pfeiffer jsk-fellows2005 18502 2013-04-21T20:54:15+00:00 1 SachaPfeiffer

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CREATE VIEW jsk_fellows AS 
    select
        users.id,
        users.name,
        users.description,
        users.location,
        users.url,
        'https://twitter.com/' || users.screen_name as twitter,
        group_concat(lists.slug) as fellowship,
        users.followers_count,
        users.created_at,
        users.verified,
        users.screen_name
    from users
        join list_members
            on list_members.user = users.id
        join lists
            on list_members.list = lists.id
    where
        lists.slug like 'jsk-fellows%'
        and lists.slug not like '%projects'
    group by users.id;
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